Newton's Law of Cooling
See the example on page 459 of your text.
Sir Isaac Newton found that the temperature of something heated
will cool down according to the function:
u(t) = Room Temp + (Heated Temp-Room Temp)ekt
where t is time
and k is some constant, depending on the material.
Example
In a 72° room, my 180° coffee will be 150° after two minutes.
I like my coffee at 120°. How long should I wait?
- Use the info about how long it takes for my coffee to get to find k
u(t) = Room Temp + (Heated Temp-Room Temp)ekt
150 = 72 + (180-72)ek2
78 = (108)e2k
e2k = 78/108 = 13/18
2k=ln(13/18)
k=.5(ln(13/18)) ≈ .5(-.3254224)=-0.1627112
So the constant of cooling for my coffee is -.1627 or so. Here is the check:
u(t) = 72+(108)e-.1627t
u(2)=72+108e(-.1627)(2)≈150°
- Solve for t
72+108e-.1627t = 120°
108e-.1627t = 48
e-.1627t = 48/108=4/9
-1627t = ln(4/9)
t ≈ (-.8109302)/(-.1627) = 5 minutes
Challenges
- In a 72° room, my 180° coffee will be 150° after two minutes.
How long will it take to get 75°?
- What is the temperture after 30 minutes?
- Boiling water (212° at sea level) is left in a 70° and after 5 minutes it is
180° What is the constant of cooling?
- Using this info from the previous question, how long will it take to have it cool to 98°?
- Heating is cooling in reverse. Use the same constant k as in #3. If an ice cube is placed in the
same room. how long will it take to become 50°? (presume the ice is 32° when frozen).
- What temperature is the water after 15 minutes?
Here is a link to my java code
Here is a link to other examples of exp and log functions from the UBC