import java.util.*;
/**
 * This is my own Free Response question do not be intimidated
 * the first question is of harder difficulty than the second one.
 *
 * @author Carlos Vega, adaptations by FC
 * @version 004/30/22
 */
public class Restaurant
{
	private ArrayList<Reservation> waitingList;

	public Restaurant()
	{
		waitingList = new ArrayList<Reservation>();
	}

	/** @returns the index, where reservation is located.
	 * If it cannot find the reservation, it will return  -1.
	 * @param the name of the customer and their party size.
	 * Precondition: name is in lower case
	 * 	or one more reservation.
	 */
	public int findReservation(String name, int seats)
	{ /* to be implemented in part (a) */ 

		
		
	}

	/** checkIn will update the waitingList
	 * If the reservation is found, it will be removed from waitingList.
	 * If it is not found, a new Reservation will be added to waitingList.
	 * Make sure not to duplicate code.  You made presume that the method
	 * written in part(a) works perfectly. 
	 * @param the name of the customer being located the party size.
	 * Precondition: name is in lower case, seats >=0
	 * Postcondition:	tables with either have one less reservation,
	 * 	or one more reservation
	 * @return true if the reservation was found, and customer is checked in
	 * 	       false if the reservation as not found, and the customer has been added to 
	 *         waitingList 
	 */

	public boolean checkIn (String name, int seats)
	{ /* to be implemented in part (b) */ 
		

	}
	// not shown in question
    public void add(Reservation r)
    {
    	waitingList.add(r);
    }

	public int getLength()
	{
		return waitingList.size();
	}

	public String toString()
	{
		String list= "Reservation list: \n";
		for (int i=0; i < waitingList.size(); i++)
		{
			list += waitingList.get(i) + "\n";
		}
		return list;
	}
}